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Vectors ` vec a=-4 hat i+3 hat k ; vec b=14 hat i+2 hat j-5 hat k`are laid off fromone point. Vector ` hat d`, which is being laid offrom the same point dividing the angle between vectors ` vec aa n d vec b`in equal halves and having the magnitude `sqrt(6),`isa. ` hat i+ hat j+2 hat k`b.` hat i- hat j+2 hat k`c. ` hat i+ hat j-2 hat k`d. `2 hat i- hat j-2 hat k`A. `hati+hatj + 2hatk`B. `hati-hatj+2hatk`C. `hati+hatj-2hatk`D. `2hati-hatj-2hatk` |
Answer» Correct Answer - A `hat a = (-4i + 3hatk)/(5) , hatb = (14hati + 2hatj - 5hatk)/(15) ` A vector `vecV` bisecting the angle between `veca and vecb` is `" "vecV = hata + hat b ` `" "= (-12hati + 9hatk + 14hati + 2hatj -5hatk)/(15)` `" " = (2hati + 2hatj + 4hatk)/(15)` Required vector `vecd = sqrt6 hat V = hat i + hatj + 2hatk` |
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