Vedan14. The range of the principle value branch of the functionY=sin

1.	Vedan14. The range of the principle value branch of the functionY=sin inverse x
Answer» Answer: We KNOW that the RANGE of the principal value branch of SIN-1(X) is (−π/2, π/2) and sin(π/4) = 1/√2. So, the principal value of sin-1(1/√2) = π/4. We know that the range of the principal value branch of sin-1(x) is (−π/2, π/2) and sin(π/2) = 1.09-Nov-2020

Vedan14. The range of the principle value branch of the functionY=sin inverse x

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We KNOW that the RANGE of the principal value branch of SIN-1(X) is (−π/2, π/2) and sin(π/4) = 1/√2. So, the principal value of sin-1(1/√2) = π/4. We know that the range of the principal value branch of sin-1(x) is (−π/2, π/2) and sin(π/2) = 1.09-Nov-2020

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Vedan14. The range of the principle value branch of the functionY=sin inverse x​

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Vedan14. The range of the principle value branch of the functionY=sin inverse x