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Velocity and acceleration of a particle at time to aret vecu (2hati+3hatj)m/s and veca = (4hatj +2hatj) m//s^(2) respectively. Find the velocity and displacement of particle at |
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Answer» SOLUTION :Here acceleration `veca=(4hati+2hatj)m//s^(2)` is constant so, we can apply `vecv= vecu+vec (at) and vecs= uvect+(1)/(2) vec (at)^(2)` substituting the proper values, we get `vecv=(2hati+3haj)+(2) (4hati+2hatj)=(hati+7hatj) m//s and` `vecs=(2) (2hati+3hatj)+(1)/(2)(2)^(2)(4hati+2hatj)=(12hatI+10 HATJ)` therefore velocity and displacement of PARTICLE at t=2s are `(10 hati+7 hatj) m//s and (12 hati+10 hatj)` m respectively. |
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