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velocity of a bodyrevolving in circular orbit very close to thesurface of a planet of radius R and mean density(I) Show that the critical2 R \sqrt{\frac{\pi \sqrt{3 G}}{3}} |
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Answer» Critical Velocity (Vc) The minimum velocity required to revolve in a circular orbit around a planet is called critical velocity. Vc=√[ ( G M ) / R ] _ _ _ _ _ ( 1 ) Where , G = Gravitational Constant M = Mass of planet R = Radius of planet The density ( ρ ) of a body can be define as mass enclosed per unit volume Therefore, ρ = M / V i.e. M = ρ V Volume of spherical planet is V = ( 4 / 3 ) π R3 The mass of planet can be given as M = ρ ( 4 / 3 ) π R3 Putting this value in equation ( 1 ) we get, Vc=√[ ( ( 4 / 3 ) G ρ π R3) / R ] Vc= 2√[ ( G ρ π R2) / 3 ] Vc= 2R√[( Gρ π ) / 3 ] |
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