Velocity of a particle moving in a straight line is v=sqrt(9+4s). Here v is in m/s and 's' displacement in meter.Mass of the particle is 2kg. The time in seconds at which average power is ((3)/(4))^(th) of the instantaneous power is :

Velocity of a particle moving in a straight line is v=sqrt(9+4s). Here

1.	Velocity of a particle moving in a straight line is v=sqrt(9+4s). Here v is in m/s and 's' displacement in meter.Mass of the particle is 2kg. The time in seconds at which average power is ((3)/(4))^(th) of the instantaneous power is :
Answer» 0.92 0.67 1.5 `3.0` Solution :Maximum energy stored in spring `=(1)/(2)MU V_("ret")^(2)=(1)/(2)((mm)/(m+m))(V_(0)^(2))=(1)/(4)mV_(0)^(2)`

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Velocity of a particle moving in a straight line is v=sqrt(9+4s). Here v is in m/s and 's' displacement in meter.Mass of the particle is 2kg. The time in seconds at which average power is ((3)/(4))^(th) of the instantaneous power is :

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