Velocity of a particle moving in a straight line is v=sqrt(9+4s). Here v is in m/s and 's' displacement in meter.Mass of the particle is 2kg. The time in seconds at which average power is ((3)/(4))^(th) of the instantaneous power is :

Velocity of a particle moving in a straight line is v=sqrt(9+4s). Here

1.	Velocity of a particle moving in a straight line is v=sqrt(9+4s). Here v is in m/s and 's' displacement in meter.Mass of the particle is 2kg. The time in seconds at which average power is ((3)/(4))^(th) of the instantaneous power is :
Answer» <html><body><p>0.92<br/>0.67<br/><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.5<br/>`3.0`</p>Solution :Maximum energy stored in spring `=(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a> V_("ret")^(2)=(1)/(2)((mm)/(m+m))(V_(0)^(2))=(1)/(4)mV_(0)^(2)`</body></html>

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Velocity of a particle moving in a straight line is v=sqrt(9+4s). Here v is in m/s and 's' displacement in meter.Mass of the particle is 2kg. The time in seconds at which average power is ((3)/(4))^(th) of the instantaneous power is :

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