1.

Velocity of particle having 1 mg mass is 72 km/hr.Its de-Broglie wavelength is ….

Answer»

<P>`3.3xx10^(-29)`
`3.3xx10^(-10)`
`3.3xx10^(-32)`
`3.3xx10^(-6)`

Solution :`m=10^(-6)` kg
`V=(72xx1000)/(3600)(m)/(s)` de-Broglie wavelength of particle ,
`lambda=(h)/(p)=(h)/(MV)`
`therefore lambda=(6.6xx10^(-34))/(10^(-6)xx20)`
`therefore lambda=3.3xx10^(-29)m`


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