Velocity of sound in air is 300 m/s. Then the distance between two successive nodes of a stationary wave of frequency 1000 Hz is :

Velocity of sound in air is 300 m/s. Then the distance between two suc

1.	Velocity of sound in air is 300 m/s. Then the distance between two successive nodes of a stationary wave of frequency 1000 Hz is :
Answer» 10 CM 20 cm 15 cm 30 cm Solution :v = 300 `ms^(-1), "" v = 1000` HZ. `lambda = (u)/(v) = (300)/(1000) = 0.3` m `lambda` = 30 cm Now distance between two consecutive nodes is x = `(lambda)/(2) `. x = `(30)/(2) = 15` cm Hence the CORRECT chioce is (C).

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Velocity of sound in air is 300 m/s. Then the distance between two successive nodes of a stationary wave of frequency 1000 Hz is :

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