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Velocity-time graph of a particle of mass (2 kg) moving in a straight line is as shown in Fig. 9.20. Find the word done by all the forces acting on the particle. .A. `400 J`B. `-400 J`C. `-200 J`D. `200 J` |
Answer» Correct Answer - C Initial velocity of the partical : `v_(1) = 2 m//s` Final velocity of the partical . `v_(f) = 0` From work energy theorm `W_("net") = Delta K.E = K_(f) - K_(i)` `(1)/(2) m (v_(f)^(2) - v_(i)^(2)) = (1)/(2) (2) (0 - 400) = - 400 J` |
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