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Verify by the method of contradiction that √3 is irrational |
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Answer» हिंदी में खोजेंहिंदी में खोजेंविरोधाभास है कि की विधि द्वारा की पुष्टि √3 तर्कहीन हैहिंदी में खोजेंविरोधाभास है कि की विधि द्वारा की पुष्टि √3 तर्कहीन हैSince both q and r are ODD, we can write q=2m−1 and r=2n−1 for some m,n∈N. We note that the lefthand side of this equation is EVEN, while the righthand side of this equation is odd, which is a CONTRADICTION. THEREFORE there exists no RATIONAL number r such that r2=3. Hence the root of 3 is an irrational number. |
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