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Verify that the cyclotron frequency omega=(eB)/m has the correct dimensions of [T]^(-1). |
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Answer» Solution :When charge particle enter perpendicular magnetic field it PROVIDES the centripetal force for revolution. So, `(MV^(2))/R=qvB` `therefore(mv)/R=qB` but `v/R=omegaandq=e` `omega=(eB)/m=v/R` `therefore[omega]=[(eB)/m]=([v])/([R])` = `(M^(0)L^(1)T^(-1))/L^(1)` = `M^(0)L^(0)T^(-1)=[T^(-1)]` |
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