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Verify that y = 4 sin 3x is a solution of the differential equation \(\frac{d^2y}{dx^2}+9y = 0.\) |
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Answer» The differential equation is \(\frac{d^2y}{dx^2}+9y = 0\) and the function that is to be proven as the solution is y = 4 sin 3x, now we need to find \(\frac{d^2y}{dx^2}.\) \(\frac{dy}{dx}\) = 12 cos 3x \(\frac{d^2y}{dx^2}\) = – 36 sin 3x Putting the values in the equation, we get, –36 sin 3x + 9(4 sin 3x) = 0, 0 = 0 As, L.H.S = R.H.S. the equation is satisfied, so hence this function is the solution of the differential equation. |
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