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Vertical displacement of a plank with a body of mass m on it is varying according to the law `y=sinomegat+sqrt(3)cosomegat`. The minimum value of `omega` for which the mass just breaks off the plank and the moment it occurs first time after t=0, are given by (y is positive towards vertically upwards).A. `sqrt(g/2),sqrt(2/6),(pi)/(sqrt(g))`B. `g/sqrt(2),2/3sqrt(pi)/g)`C. `sqrt(g/2),(pi)/3)sqrt(2/g)`D. `sqrt(2g),sqrt((2pi)/(3g))`

Answer» Correct Answer - A


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