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व्हाट इज द सेंटर ऑफ ग्रेविटी ऑफिस semi-circle ऑफ डायमीटर 12 सेंटीमीटर |
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Answer» -step explanation:To Find : Center of GravitySolution:Diameter = 12 cmRadius = 6 cmTaking center at ( 0 , 0) and SEMICIRCLE above X axisBecause of symmetry center of gravity will lie of y AXISA = (1/2)πr² = (1/2)π(6)² = 18π cm² ( area of semicircle)x² + y² = r² = 6²=> x² = (6² - y²)=> x = √(36 - y²)Let ASSUME 36 - y² = z => -2ydy = dz=> 2ydy = -dz on substituting on integratingApplying limits 0 to 6216/27π= 8/π cm= 2.5465 cmHence centre of gravity of a semi circle of diameter 12 cmwill be at a height of 8/π cm or 2.5465 cm from the center of Semicircle |
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