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Vi) The lengths of the sides of a triangular park are 90 m, 70 m, and 40 m, find its area (a)1340 sqm(b) 1344 sq m(c) 1440 sq m (d) 1444 sqm |
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Answer» (b) 1344 sq mStep-by-step explanation:Solution - Area of a triangle WHOSE three sides are given is given by HERON's formula. A = SQRT (s (s - a) ( s - b) (s - c)) Where s is the half perimeter. s = (a + b + c) / 2 Given: a = 40m, b = 90m, c = 70m s = (40 + 90 + 70) / 2 = 200/2 = 100 m Area of the triangle A = sqrt (s (s - a) ( s - b) (s - c)) = sqrt (100 * (100 - 40) * (100 - 90) * ( 100 - 70)) = sqrt ( 100 * 60 * 10 * 30) = 10 sqrt (18000) = 10 sqrt (3600 * 5) = 10 * 60 * sqrt 5 = 10 * 60 * 2.24 = 1344 sq. m Area of the triangular garden = 1344 sq. mHope its helpful..Mark me Brainliest!! |
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