1.

W_(1),W_(2) and W_(3) are the different sizes of windows 1, 2, and 3 respectively placed in a vertical plane. A particle is thrown up in the vertical plane. Let t_(1),t_(2) and t_(3) are the time taken to cross the window W_(1), W_(2) and W_(3) respectively and DeltaV_(1), DeltaV_(2) and DeltaV_(3) are the change in speed after respective window cross.

Answer»

AVERAGE speed of the particle passing the windows may be equal if `W_(1)ltW_(2)ltW_(3)`
Average speed of the particle passing the windows may be equal if `W_(1)gtW_(2)gtW_(3)`
If `W_(1)=W_(2)=WP_(3)`, the change in speed of the particle while crossing the windows will satisfy `DeltaV_(1)ltDeltaV_(2)ltDeltaV_(3)`
If `W_(1)=W_(2)=W_(3)`, the time taken by particle to CROSS the windows will satisfy `t_(1)LT t_(2) lt t_(3)`

SOLUTION :As going up, speed of the particle is decreasing and hence the time taken in crossing the windows will be `t_(1)lt t_(2) lt t_(3)` (if `W_(1)=W_(2)=W_(3)`)
Simultaneously `DeltaVpropt`
`:.DeltaV_(1)ltDeltaV_(2)lt DeltaV_(3)`
For UNEQUAL windows `t_(1)=t_(2)=t_(3)` may be if `W_(3)ltW_(2)ltW_(1)`


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