Water is flowing through a cylindrical pipe of internal diameter 2cm, into a cylindrical tank of base radius 40 cm at the rate of 0.7m/sec. By how much will the water rise in the tank in half an hour?

Water is flowing through a cylindrical pipe of internal diameter 2cm,

1.	Water is flowing through a cylindrical pipe of internal diameter 2cm, into a cylindrical tank of base radius 40 cm at the rate of 0.7m/sec. By how much will the water rise in the tank in half an hour?
Answer» 395.64 litersSteps:Volume of Water flowing through the PIPE is given by the formula:Cross Sectional Area of the Pipe × Rate of FlowAccording to the question,Diameter of the pipe is 2 cm. Hence the cross sectional area of the pipe can be CALCULATED as:→ Area of Circle = πr²→ Area of Circle = 3.14 × 1 × 1 = 3.14 cm² Hence Volume of water flowing per SECOND is given as:→ Volume = 3.14 cm² × 0.7 m/s ( 70 cm/s )→ Volume = 219.8 cm³ / sHence 219.8 cm³ of water is flowing per second. Hence for 30 minutes, the amount of water flowing is given as:→ Volume after 30 minutes = 30 × 60 × 219.8→ Volume after 30 minutes = 395640 cm³1 cm³ = 0.001 literHence volume of water in LITERS is given as: 395.64 liters.Hence after 30 minutes, the volume of water PRESENT in the cylindrical tank is 395.64 liters.