1.

Water rises to a height of 10 cm in capillary tube and mercury falls to a depth of 3.42 cm in the same tube. If the density of mercury is 13.6 g cm^(-3) and angle of contact is 135°, the ratio of the surface tensions for water and mercury is :

Answer»

`1:5.57`
`1:3.57`
`1:6.57`
`:1.1.57`

SOLUTION :`(T_(omega))/(T_(m))=(h_(omega)d_(omega))/(costheta_(omega))xx(costheta_(m))/(h_(m)xxd_(m))=(10xx1xxcos135^(@))/(1xx3.42xx13.6)`
`=(10xx1)/(3.42xx1.414xx13.6)=1/(6.57)`
CORRECT choice is (C).


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