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Water rises to height of 20mm in capillary tube hving cross sectional area A. If the area of the cross section of the tube is made A/4, then find the rise of height water. |
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Answer» Solution :`(Delta_2)/(Delta_1) = (r_2^2)/(r_1^2)` `THEREFORE (A/4)/A = 1/4 = (r_2^2)/(r_1^2)` `therefore (r_2)/(r_1)` = 1/2` `therefore (r_1)/(r_2)` =2 For capillary RISE `h_1 r_1 = h_2 r_2` `therefore h_2 = (h_1 r_1)/r_2 = 20 XX 2 = 40 mm = 4cm` |
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