1.

Wavelenght of given light waves in air and in a medium are 6000 Å respectively. The critical angle is :

Answer»

`tan^(-1)((2)/(3))`
`tan^(-1)((3)/(2))`
`sin^(-1)((2)/(3))`
`sin^(-1)((3)/(2))`

Solution :(c ) `(1)/(sinC) = (lambda_(1))/(lambda_(2))`
`(1)/(sinC) = (6000)/(3000)`
`(1)/(sinC) = (6)/(3) = (3)/(2)`
`sin C = (2)/(3)`
`C = sin^(-1) ((2)/(3))`


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