Saved Bookmarks
| 1. |
Wavelength of an electron having energy 10 keV ……..Å |
|
Answer» 0.12 `=(6.6xx10^(-34))/(sqrt(2xx9.1xx10^(-31)xx10^(4)xx1.6xx10^(-19)))` `=0.12xx10^(-10)m` `therefore lambda=0.12 Å` |
|