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Wavelength of light in air is 6000Å. Calculate its wavelength in water(n =4/3) and glass(n= 3/2). |
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Answer» Solution :Data supplied `c=3xx10^(8)MS^(-1),"" LAMDA=6000Å=6000xx10^(-10)m` Frequency `v=c/(lamda)=(3xx10^(8))/(6000xx10^(-10))=(3xx10^(8))/(6xx10^(-7))=5xx10^(-14)Hz` In water `n_(wa)=4/3=c/(c_(W))` `c_(w)=c/(n_(wa))=(3xx10^(8))/((4//3))=9/4xx10^(8)m//s "" :. lamda_(w)=(c_(w))/v=(9xx10^(8))/(4xx5xx10^(14))=4500Å` In glass `n_(GA)=3/2=c/(c_(g))"" :. c_(g)=c/(n_(ga))=(3xx10^(8))/(3//2)=2xx10^(8)m//s` `:.lamda_(g)=(c_(g))/v=(2xx10^(8))/(5xx10^(14))=4xx10^(-7)=4000Å` |
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