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Wavelength of light used in an optical instrument are `lambda_(1)=400 Å ` and `lambda_(2)=5000 Å`, then ratio of their respective resolving power (corresponding to `lambda_(1)` and `lambda_(2))` isA. `16:25`B. `9:1`C. `4:5`D. `5:4` |
Answer» Correct Answer - D `R.P.=(1)/(lambda)implies((R.P.)_(1))/((R.P.)_(2))=(l_(2))/(l_(1))=(5)/(4)` |
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