1.

Wavelength of particle moving with momentum 2xx10^(-28) kg ms^(-1) will be ……

Answer»

`3.3xx10^(-6)m`
`3.3xx10^(5)m`
`3.3xx10^(-4)m`
1.30 m

Solution :de-Broglie wavelength of PARTICLE,
`lambda=(h)/(MV)=(h)/(p)`
`THEREFORE lambda=(6.6xx10^(-34))/(2xx10^(-28))`
`therefore lambda=3.3xx10^(-6)m`


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