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Wavelength of photon having 35 keV energy will be……..(h=6.625xx10^(-34))J-s,c=3xx10^(8)ms^(-1),1eV=1.6xx10^(-19)J). |
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Answer» `35xx10^(-12)m` `therefore =(hc)/(E )=(6.625xx10^(-34)xx3xx10^(8))/(35xx10^(3)xx1.6xx10^(-19))` |
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