1.

wedge_(m)^(0)H_(2)O is equal to____

Answer»

`wedge_(m(HCl))^(0)+wedge_(m(NAOH))^(0)-wedge_(m(NaCl))^(0)`
`wedge_(m(HNO_(3)))^(0)+wedge_(m(NaNO_(3)))^(0)-wedge_(m(NaOH))^(0)`
`wedge_((HNO_(3)))^(0)+wedge_(m(NaOH))^(0)-wedge_(m(NaOH_(3)))^(0)`
`wedge_(m(NH_(4)OH))^(0)+wedge_(m(HCl))^(0)-wedge_(m(NH_(4)Cl))^(0)`

Solution :`wedge_(m(H_(2)O))^(@)=lamda_(H^(+))^(@)+lamda_(OH^(-))^(@)`. We GET this expressions from (a) and (d).


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