1.

wedge_(NH_(4)OH)^(@) is ___________.

Answer»

`wedge_(NH_(4)OH)^(@)=wedge_(NH_(4)CL)^(@)+wedge_(NAOH)^(@)-wedge_(NaCl)^(@)`
`wedge_(NH_(4)OH)^(@)=wedge_(NH_(4)Cl)^(@)-wedge_(NaOH)^(@)-wedge_(NaCl)^(@)`
`wedge_(NH_(4)OH)^(@)=wedge_(NH_(4)OH)^(@)+wedge_(NaCl)^(@)-wedge_(NaCl)^(@)`
`wedge_(NH_(4)OH)^(@)=wedge_(NH_(4)Cl)^(@)+wedge_(NaCl)^(@)-wedge_(NaOH)^(@)`

Answer :A


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