1.

Weight of Ca(OH)_(2) needed to prepare 250 ml of solution with pH=13

Answer»

0.925 g
0.0125 g
0.25 g
1 g

Solution :We know, `[H^(+)]=10^(-pH)=10^(-13)`
`therefore[OH^(-)]=(10^(-14))/(10^(-13))=10^(-1)`
hence, NORMALITY of solution=0.1
We know, `w=(NEV)/(1000)=(0.1xx74xx250)/(2xx1000)=0.925gm`


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