What amount of energy (in eV) should be added to an electron to reduce its de-Broglie its de-Broglie wavelength from 100 to 50 pm? Given `h=6.62xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg`.

What amount of energy (in eV) should be added to an electron to reduce

1.	What amount of energy (in eV) should be added to an electron to reduce its de-Broglie its de-Broglie wavelength from 100 to 50 pm? Given `h=6.62xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg`.
Answer» From `lambda=(2pi ħ)/(P)=(2pi ħ)/(sqrt(2mT))` we find `T=(4pi^(2) ħ^(2))/(2 m lambda^(2))=(2pi^(2) ħ^(2))/(m lambda^(2))` Thus `T_(2)-T_(1)=(2pi^(2) ħ^(2))/(m)((1)/(lambda_(2)^(2))-(1)/(lambda_(1)^(2)))` Substitution gives `Delta T= 451 eV= 0.451ke V`.

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What amount of energy (in eV) should be added to an electron to reduce its de-Broglie its de-Broglie wavelength from 100 to 50 pm? Given `h=6.62xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg`.

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