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What are minimum and maximum functional values for this?? do it with explain the question !! |
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Answer» n: y = 2x³ - 15x² + 36x + 1Find the first derivative:f(x) = 2x³ - 15x² + 36x + 1F'(x) = 6x² - 30x + 36Find the MAX and min POINTSTHE max and min VALUES happens when the first derivative = 06x² - 30x + 36 = 0x² - 5X + 6 = 0 (x - 2)(x - 3) = 0x = 2 or x = 3Find the second derivative:f'(x) = 6x² - 30x + 36f''(x) = 12x - 30When x = 2f''(2) = 12(2) - 30 = - 6 f''(2) < 0 (It is a maximum point) When x = 3f''(3) = 12(3) - 30 = -6 f''(3) > 0 (It is a minimum point) Answer: The maximum point occurs at x = 2 and minimum points at x = 3 |
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