What are the last two digits of the number `9^(200)`A. 19B. 21C. 41D.

1.	What are the last two digits of the number `9^(200)`A. 19B. 21C. 41D. 1
Answer» Correct Answer - D Using binomial theorem `9^(200)=(1+8)^(200)` `=1+8.200+(200xx199)/(2!)xx8^(2)+…..` `=1+1600+1273600+….` From above, it is clear that the last two digits of the number `9^(200)` are 0.1

Discussion

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