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What concentration of `CO_(2)` be in equilibrium with `2.5xx10^(-2) mol L^(-1)` of CO at `100^(@)C` for the reaction: `FeO(s)+CO(g) hArr Fe(s)+CO_(2)(g), K_(c)=5.0` |
Answer» `K_(c)=([CO_(2)])/([CO])` `:. 5=([CO_(2)])/(2.5xx10^(-2))` `:. [CO_(2)]` at equilibrium `=2.5xx10^(-2)xx5` `=12.5xx10^(-2)mol litre^(-1)` |
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