1.

What concentration of `CO_(2)` be in equilibrium with `2.5xx10^(-2) mol L^(-1)` of CO at `100^(@)C` for the reaction: `FeO(s)+CO(g) hArr Fe(s)+CO_(2)(g), K_(c)=5.0`

Answer» `K_(c)=([CO_(2)])/([CO])`
`:. 5=([CO_(2)])/(2.5xx10^(-2))`
`:. [CO_(2)]` at equilibrium `=2.5xx10^(-2)xx5`
`=12.5xx10^(-2)mol litre^(-1)`


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