1.

What conclusion may be drawn from the following results of (a) and (b) ? (a) If a 1 xx 10^(-3) kg body is travelling along the x-axis at 1 m/s within 0.01m/s. Calculate the theoretical uncertainty in its position. (b) If an electron is travelling at 100 m/s within 1m/s, calculate the theoretical uncertainty in its position. [h= 6.63 xx 10^(-34)J.s, mass of electron =9.109 xx 10^(-31)kg]

Answer»

Solution :(a) The velocity has an uncertainty of 0.02m/s. (from 0.99 to 1.01 m/s)
`therefore Delta x= (h)/(4pi m Delta v)= (6.63 xx 10^(-34) (J.s))/((4 xx 3.14) (1 xx 10^(-3) kg) (0.02m//s))`
`=3 xx 10^(-30)` metre
(B) `Delta x= (6.63 xx 10^(-34) (J.s))/((4 xx 3.14) (9.109 xx 10^(-31)kg) (2m//s))`
`~~3 xx 10^(-5)` metres


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