1.

What current strength in amperes will be required to liberate 10 g of iodine from potassium iodide solution in one hour ?

Answer»

SOLUTION : `=(96,500)/(127)xx"10 COLUMB"`
LET the CURRENT strength be = I
Time in seconds `=1xx60xx60`
We KNOW that the quantity of electricity, Q, used is given by the expression
`Q=Ixx" time in seconds"`
Curernt strength, `I=(Q)/(t)=(96,500xx10)/(127xx60xx60)`
= 2.11 ampere.


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