

InterviewSolution
Saved Bookmarks
1. |
What do you mean by terms 'in phase' ? |
Answer» <html><body><p></p>Solution :Let `I_1` and `I_2` be the <a href="https://interviewquestions.tuteehub.com/tag/intensities-16135" style="font-weight:bold;" target="_blank" title="Click to know more about INTENSITIES">INTENSITIES</a> of <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> <a href="https://interviewquestions.tuteehub.com/tag/beams-894101" style="font-weight:bold;" target="_blank" title="Click to know more about BEAMS">BEAMS</a> having <a href="https://interviewquestions.tuteehub.com/tag/amplitudes-859603" style="font-weight:bold;" target="_blank" title="Click to know more about AMPLITUDES">AMPLITUDES</a> `a_1` and `a_2.` <br/> `I_1/I_2=9/1` <br/> But,`I_1/I_2=a_1^2/a_2^2 `<br/>` therefore a^2_1/a_2^2=9/1` or, `a_1/a_2=3/1` <br/> If `a_max` and `a_min` are the amplitudes are maxima and <a href="https://interviewquestions.tuteehub.com/tag/minima-1097152" style="font-weight:bold;" target="_blank" title="Click to know more about MINIMA">MINIMA</a>. <br/>`a_max/a_min =a_1+a_2/a_1-a_2=3+1/3-1=4/2=2/1` <br/> `I_max/I_min=a^2_max/a^2_min=4/1`</body></html> | |