InterviewSolution
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InterviewSolution
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What do you mean by terms 'in phase' ? |
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Answer» Solution :Let `I_1` and `I_2` be the INTENSITIES of TWO BEAMS having AMPLITUDES `a_1` and `a_2.` `I_1/I_2=9/1` But,`I_1/I_2=a_1^2/a_2^2 ` ` therefore a^2_1/a_2^2=9/1` or, `a_1/a_2=3/1` If `a_max` and `a_min` are the amplitudes are maxima and MINIMA. `a_max/a_min =a_1+a_2/a_1-a_2=3+1/3-1=4/2=2/1` `I_max/I_min=a^2_max/a^2_min=4/1` |
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