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What fraction (n/N) of the lattice sites are vacant at 298 K for a crystal in which the energy required to make a defect is 1 eV.(1 eV = 1.602 xx 10^(-19) J) |
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Answer» Solution :We have, `n/N =e^(-(E_(0)/(KT))` `ln n/N = -E_(v)/(kT)` or `logn/N = -E_(v)/(2.303kT) = -(1.602 xx 10^(-19))/(2.303 xx (8.314//6.022 xx 10^(23)) xx 298)` On solving, `n/N = 1.24 xx 10^(-17)` |
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