InterviewSolution
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InterviewSolution
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What fraction of hydrogen atoms is in the state with the principle quantum number n=2 at a temperature T=3000K? |
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Answer» Solution :By Boltzmann formula `(N_(2))/(N_(1))=(g_(2))/(g_(1)) e^(DeltaE//kT)`. Here `DeltaE=` energy difference between `N=1` and `n=2` STATES `=13.6(1-(1)/(4))eV=10.22eV` `g_(1)=2` and `g_(2)=8` (counting `2s` & `2P` states).Thus `(N_(2))/(N_(1))=4e^(-10.22xx1.602xx10^(-19)//1.38xx10^(-23)xx3000)=2.7xx10^(-17)` Explicity `ETA=(N_(2))/(N_(1))=n^(2)e^(-DeltaE//kT),DeltaE_(n)= ħR(1-(1)/(n^(2)))` for the nth excited state beacuse teh degeneracy of the state with principle quantum number `n is 2n^(2)`. |
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