What happens if you try to compile and run this program? #include int main(void) {int i = 3, j = i - 2 * i;switch (ij) {case 1: i++;da se2: j --;case 0: j+-; break;default: j = 0;Sprintf ("%d", ++i);return 0;

What happens if you try to compile and run this program? #include in

1.	What happens if you try to compile and run this program? #include int main(void) {int i = 3, j = i - 2 * i;switch (ij) {case 1: i++;da se2: j --;case 0: j+-; break;default: j = 0;Sprintf ("%d", ++i);return 0;
Answer» the program output4Explanation:What happens if you try to COMPILE and run this program? #include int main(void) { int x = 1, y = 1; float K = -1e0, m = 2e1; PRINTF("%d\n", (x >= y) + (x >= y) + (k >= y) + (m >= k) + ('q' <= 'z')); return 0; } the program OUTPUTS 4the program outputs 1the program outputs 3the program outputs 2HOPE THAT WAS helpful