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What happens to the drift velocity of electron and to the resistance if length of conductor is doubled keeping potential differnece unchanged ?

Answer»

Solution :`v_(d)=(EE)/(m) TAU=(eV)/(ml)* tau [ E=(V)/(l)]`keeping V constant, if l is DOUBLED, `v_(d)` is halved. Again keeping area constant. If length is doubled, if R will be doubled `[R alpha,1` if a is constant].


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