What happens to the pressure, P, of an ideal gas if the temperature is increased by a factor of 2 and the volume is increased by a factor of 8 ?

What happens to the pressure, P, of an ideal gas if the temperature is

1.	What happens to the pressure, P, of an ideal gas if the temperature is increased by a factor of 2 and the volume is increased by a factor of 8 ?
Answer» P DECREASES by a factor of 16 P decreases by a factor of 4 P decreases by a factor of 2 P increases by a factor of 4 Solution :USE the ideal gas LAW, `P'=(nRT')/(V')=(NR(2T))/(8V)=(1)/(4)(nRT)/(V)=(1)/(4)P`

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What happens to the pressure, P, of an ideal gas if the temperature is increased by a factor of 2 and the volume is increased by a factor of 8 ?

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