What happens to the rms speed of the molecules in a sample of helium gas if the temperature is increased from -73^(@)C to 527^(@)C?

What happens to the rms speed of the molecules in a sample of helium g

1.	What happens to the rms speed of the molecules in a sample of helium gas if the temperature is increased from -73^(@)C to 527^(@)C?
Answer» Solution :When we use the ideal Gas law or the formulas for `v_(rms)`, we have to use ABSOLUTE temperatures-that is, temperatures expressed in kelvins. The conversion between degrees celsius and kelvins is `T_(""^(@)C)+273=T,` so `-73^(@)C=200K and 527^(@)C=800K`. therefore, the absolute temperature of the gas is increased by a factor off 4 (from 200 K to 800 K). since `v_(rms)` is proportional to `sqrt(T)`, if T INCREASES by a factor of 4, then `v_(rms)` increases by a factor of `sqrt(4)=2`.

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What happens to the rms speed of the molecules in a sample of helium gas if the temperature is increased from -73^(@)C to 527^(@)C?

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