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What happens when ethanoic acid reacts with the following reagents? (i) LiAIH_4 (ii) Red P, HI |
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Answer» <P> SOLUTION :(i) When ethanoic acid reacts by` LiAlH_4`, partial reduction take place and ethanol is formed as a PRODUCT.`underset{"ethanoicacid")(CH_3-oversetunderset(||)(O)(C )-OH) underset(4[H])overset(LiAlH_4)(to)underset("ethanol")(CH_3 - CH_2OH + H_2O)` (ii) When ethanoic acid is treated with HI and red PHOSPHOROUS, complete reduction take place and alkane is formed as a product. `underset("ethanoic acid")(CH_3-oversetunderset(||)(O)(C ) - OH + 6HI) underset(473K)overset(Red P)(to) underset("ethane")(CH_3 - CH_3 + 3I_2 + 2H_2O)` |
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