What happens when n-butyl chloride is treated with alcoholic KOH. – InterviewSolution

1.	What happens when n-butyl chloride is treated with alcoholic KOH.
Answer» SOLUTION :The reactions are explained as under : `underset("n-Butyl CHLORIDE") (CH_(3)CH_(2) - ) CH_(2) - CH_(2)Cl + KOH (alc.) underset("DEHYDROHALOGENATION ")overset (Delta ) to CH_(3)CH_(2) - CH = CH_(2) + KCl + H_(2) O `

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