1.

What happens when XeF_(4) reacts with SbF_(5) ?

Answer»

Solution :`XeF_(4)` REACTS with fluoride ion acceptor such as `SbF_(5)` to form cationic species.
`XeF_(4) + underset("Fluoride ion acceptor")(SbF_(4)) RARR [XeF_(3)]^(+)[SbF_(6)]^(-)`


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