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What happens when XeF_(6) reacts 2.5 M solution of NaOH? |
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Answer» SOLUTION :When `XeF_(6)` reacts with 2.5 of `NaOH`, sodium per XENATE is obtained. `2XeF_(6)+16NaOHrarr underset("(sodium perxenate)")(Na_(4)XeO_(6))+Xe+O_(2)+12NaF+8H_(2)O` |
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