What hydrogen-like ion has the wavelength difference between the first lines of the Balmer Lyman series equal to `59.3nm`?

What hydrogen-like ion has the wavelength difference between the first

1.	What hydrogen-like ion has the wavelength difference between the first lines of the Balmer Lyman series equal to `59.3nm`?
Answer» From the formula of the previous problem `Delta lambda=(176 pi c)/(15 Z^(2)R)` or `Z=sqrt((176pi c)/(15R Delta lambda))` Substitution of `Delta lambda = 59.3nm` and `R` and the previous gives `Z=3` This identifies the ion as `Li^(++)`

Discussion

No Comment Found

Related InterviewSolutions

Using Eq.(6.2e), find the probability `D` of a particle of mass `m` and energy `E` tunneling through the potential barrier shown in fig. where `U(x)=U_(0)(1-x^(2)//l^(2))`.
Employing Eq.(6.2e), find the probability `D` of an electron with energy `E` tunneling through a potential barrier of width `l` and height `U_(0)` provided the barrier is shaped as shown: (a) In fig 6.4 (b) in figure 6.5.
Employing the uncertainty principle, estimate the minimum kinetic energy of an electron confined within a region whose sizes is `l=0.20nm`.
In Bohr’s model of hydrogen atom, which of the following pairs of quantities are quantizedA. Energy and linear momentumB. Linear and angular momentumC. Energy and angular momentumD. None of the above
when a hydrogen atom is raised from the ground state to an excited stateA. P.E. increases and K.E. decreasesB. P.E. decreases and K.E. increasesC. Both kinetic energy and potential energy increaseD. Both K.E. and P.E. decrease
In Bohr model of the hydrogen atom, the lowest orbit corresponds toA. Infinite energyB. The maximum energyC. The minimum energyD. Zero energy
Which of the following statements about the Bohr model of the hydrogen atom is false ?A. Acceleration of electron in `n = 2` orbit is less than that in `n = 1` orbiB. Angular momentum of electron in `n = 2` orbit is more than that in `n = 1` orbitC. Kinetic energy of electron in `n = 2` orbit is less than that in `n = 1` orbiD. Potential energy of electron in `n = 2` orbit is less than that in `n = 1` orbit
An electron in the `n = 1` orbit of hydrogen atom is bound by `13.6 eV`. If a hydrogen atom I sin the `n = 3` state, how much energy is required to ionize itA. 13.6 eVB. 4.53 eVC. 3.4 eVD. 1.51 eV
The wavelength of the first line of Balmer series is `6563 Å`. The Rydbergs constant fro hydrogen is aboutA. `1.09 xx 10^(7)` per mB. `1.09 xx 10^(8) per m`C. `1.09 xx 10^(9) per m`D. `1.09 xx 10^(5) per m`
An electron in the `n = 1` orbit of hydrogen atom is bound by `13.6 eV`energy is required to ionize it isA. 13.6 eVB. 6.53 eVC. 5.4 eVD. 1.51 eV

What hydrogen-like ion has the wavelength difference between the first lines of the Balmer Lyman series equal to `59.3nm`?

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment