Saved Bookmarks
| 1. |
What is a period of revolution of earth satellite ? Ignore the height of satellite above the surface of earth. Given : The value of gravitational acceleration g= 10 m s^(-2) Radius of earta R_(E)= 6400 km. Take pi=3.14. |
|
Answer» 85 minutes `T = 5024s = 83.73` MIN |
|