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What is (-dCa/dt) =kCa^2 ?(a) Third order reaction(b) First order reaction(c) Second Order reaction(d) Fourth Order reactionThis question was posed to me in exam.This interesting question is from Types of Reactions in chapter Chemical Process Kinetics of Unit Processes

Answer» RIGHT option is (c) SECOND Order REACTION

The explanation is: In a chemical reaction the rate EQUATION of the reaction is written in the following FORM: (-dCa/dt) =kCa^2.


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