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What is `DeltaG^(ɵ)` for the following reaction? `1/2 N_(2)(g)+3/2 H_(2)(g) hArr NH_(3)(g), K_(p)=4.42xx10^(4)` at `25^(@)C`A. `-26.5 kJ mol^(-1)`B. `11.5 kJ mol^(-1)`C. `-2.2 kJ mol^(-1)`D. `-0.97 kJ mol^(-1)` |
Answer» Correct Answer - A `DeltaG^(ɵ)=-2.303RT log K_(p)` `=-2.303xx8.314xx298.15xxlog (4.42xx10^(4))` `=-26.5 kJ "mol"^(-1)` |
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