1.

What is DeltaU for the processdescribed by figure . Heat supplied duringtheprocess q= 100 kJ

Answer»

`+50 kJ`
` -50 kJ`
`-150 KJ`
`+ 150 kJ`

Solution :`DELTAU =q + W`
` = 100 -[1 xx 1 + 1//2xx 1]"BAR" m^(3)""("1 bar " m^(3) = 10^(5) J= 100 k)`
`= - 50 kJ`


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